#!/usr/bin/env python3 # synacor.py - An implementation of the Synacor Challenge # Copyright © 2017 RunasSudo # # This program is free software: you can redistribute it and/or modify # it under the terms of the GNU Affero General Public License as published by # the Free Software Foundation, either version 3 of the License, or # (at your option) any later version. # # This program is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the # GNU Affero General Public License for more details. # # You should have received a copy of the GNU Affero General Public License # along with this program. If not, see . import re import struct import sys import tarfile IV_LEN = 3 CODE_LEN = 12 # Emulate 0731 def generate_code(R0, R1, R2, R3): R1data = SYN_MEM[R1+1:R1+1+SYN_MEM[R1]] R3data = SYN_MEM[R3+1:R3+1+SYN_MEM[R3]] assert len(R3data) == IV_LEN done = False while not done: code = '' for i in range(CODE_LEN): R5 = i % IV_LEN R6 = R3data[R5] R6 = (R6 * 0x1481) % 0x8000 R6 = (R6 + 0x3039) % 0x8000 R3data[R5] = R6 R6 = R0 ^ R6 R6 = R6 % len(R1data) if R6 + 1 <= R2: done = True R6 = R1data[R6] code += chr(R6) return code def mirror_code(code): alphabet1 = 'dbqpwuiolxv8WTYUIOAHXVM' alphabet2 = 'bdpqwuiolxv8WTYUIOAHXVM' mirrored_code = '' for letter in reversed(code): if letter not in alphabet1: raise Exception('Cannot mirror unknown letter ' + letter) mirrored_code += alphabet2[alphabet1.index(letter)] return mirrored_code # Read code into memory SYN_MEM = [0] * 32768 with tarfile.open(sys.argv[1], 'r:gz') as challenge_file: with challenge_file.extractfile('challenge.bin') as data: i = 0 while True: byteData = data.read(2) if len(byteData) < 2: break SYN_MEM[i] = struct.unpack('