78 lines
2.0 KiB
Python
Executable File
78 lines
2.0 KiB
Python
Executable File
#!/usr/bin/env python3
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# synacor.py - An implementation of the Synacor Challenge
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# Copyright © 2017 RunasSudo
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#
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# This program is free software: you can redistribute it and/or modify
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# it under the terms of the GNU Affero General Public License as published by
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# the Free Software Foundation, either version 3 of the License, or
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# (at your option) any later version.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU Affero General Public License for more details.
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#
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# You should have received a copy of the GNU Affero General Public License
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# along with this program. If not, see <http://www.gnu.org/licenses/>.
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import struct
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import sys
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IV_LEN = 3
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CODE_LEN = 12
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# Emulate 0731
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def generate_code(R1, R2, R3, R4):
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R2data = SYN_MEM[R2+1:R2+1+SYN_MEM[R2]]
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R4data = SYN_MEM[R4+1:R4+1+SYN_MEM[R4]]
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assert len(R4data) == IV_LEN
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done = False
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while not done:
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code = ''
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for i in range(CODE_LEN):
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R6 = i % IV_LEN
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R7 = R4data[R6]
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R7 = (R7 * 0x1481) % 0x8000
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R7 = (R7 + 0x3039) % 0x8000
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R4data[R6] = R7
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R7 = R1 ^ R7
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R7 = R7 % len(R2data)
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if R7 + 1 <= R3:
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done = True
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R7 = R2data[R7]
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code += chr(R7)
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return code
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# Read code into memory
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SYN_MEM = [0] * 32768
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with open(sys.argv[1], 'rb') as data:
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i = 0
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while True:
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byteData = data.read(2)
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if len(byteData) < 2:
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break
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SYN_MEM[i] = struct.unpack('<H', byteData)[0]
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i += 1
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# Emulate 06bb
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for R2 in range(0x17b4, 0x7562):
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R1 = SYN_MEM[R2]
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R1 ^= pow(R2, 2, 32768)
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R1 ^= 0x4154
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SYN_MEM[R2] = R1
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# Calls to 0731
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CODE_PARAMS = [
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(0x0058, 0x650a, 0x7fff, 0x6e8b), # R1 from the maze
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(0x1092, 0x650a, 0x7fff, 0x6eed),
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(0x6486, 0x650a, 0x7fff, 0x7239), # R1 is R8 from Ackermann
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(0x0b3b, 0x650a, 0x7fff, 0x73df), # R1 from the dots on the coins
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(0x7714, 0x653f, 0x0004, 0x74f6), # R1 based on solution to vaults
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]
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for cp in CODE_PARAMS:
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print(generate_code(*cp))
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